2019 Year 12 IB Extended Essays

C ALCULATIONS Example calculations uses results of 2.5g, 5 th ring = #

= 45 + 43 + 46 3 = 45 (2 )

P ROCESSED D ATA 1 T ABLE 3: T ABLE SHOWING AVERAGE NUMBER OF RINGS FORMED AS WELL AS DISTANCE OF RING FROM GEL SURFACE . Mass of Cobalt (II) Distance of ring from gel surface of nth ring. Measured in cm ± 1 mm

Number of rings formed

Chloride ± 0.01 g

Ring Number

5

6

7

8

9

10

11

12

13

2.50 3.00 3.50 4.00 4.50

17 23 25 25 21

45 30 23 23 12

46 32 24 24 13

46 33 25 25 14

48 34 26 26 15

49 35 27 27 16

50 36 28 29 18

51 38 29 30 19

52 39 30 32 20

54 40 32 33 21

Using the data from above, the average spacing coefficient of the structures was calculated by using the following formula: = +1 E XAMPLE CALCULATION 1 = +1 Spacing coefficient of the ninth (9 th ) band of structure of 3 grams of cobalt (II) chloride X 9 = 34 mm, X10 =35 mm = +1 = 35 34 = 1.0

13